-16t^2+850=0

Solution for -16t^2+850=0 equation:

-16t^2+850=0

a = -16; b = 0; c = +850;
Δ = b2-4ac
Δ = 02-4·(-16)·850
Δ = 54400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{54400}=\sqrt{1600*34}=\sqrt{1600}*\sqrt{34}=40\sqrt{34}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{34}}{2*-16}=\frac{0-40\sqrt{34}}{-32}
=-\frac{40\sqrt{34}}{-32}
=-\frac{5\sqrt{34}}{-4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{34}}{2*-16}=\frac{0+40\sqrt{34}}{-32}
=\frac{40\sqrt{34}}{-32}
=\frac{5\sqrt{34}}{-4}
$